L,M,J and Q are $$16th$$ group elements of Modern periodic table. The correct trend of magnitude of dissociation constant (ka) of their hydrides is $$H2L$$ $$H2M$$ $$H2J$$ $$H2Q$$. The element ‘M’ in the sequence is

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L,M,J and Q are $$16th$$ group elements of Modern periodic table. The correct trend of magnitude of dissociation constant (ka) of their hydrides is $$H2L$$ > $$H2M$$ > $$H2J$$ > $$H2Q$$. The element ‘M’ in the sequence is

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Down the group as the size of the atom increases affinity of hydrogen towards central atom decreases. $$Thereforea)$$ $$X-H$$ bond enthalpy decreases….$$O-H$$>$$S-H$$>$$Se-H$$>$$Te-H$$;$$b)$$ Thermal stability decreases….$$H2O$$>$$H2S$$>$$H2Se$$>$$H2Te$$;$$H2O$$ and $$H2S$$ are exothermic products, remaining three hydrides are endothermic products.$$c)$$ Reducing power increases…..$$H2OH2S$$>$$H2Se$$>$$H2Te$$;Down the group as vanderwaal's forces increasesMelting and boiling points increasesExpected BP and MP….$$H2OH2S$$>$$H2Se$$>$$H2Te$$;

L,M,J and Q are 16^th group elements of Modern periodic table. The correct trend of magnitude of dissociation constant (k_a) of their hydrides is H₂L > H₂M > H₂J > H₂Q. The element ‘M’ in the sequence is

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L,M,J and Q are 16th group elements of Modern periodic table. The correct trend of magnitude of dissociation constant (ka) of their hydrides is H2L > H2M > H2J > H2Q. The element ‘M’ in the sequence is

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Ready to Test Your Skills?

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L,M,J and Q are 16^th group elements of Modern periodic table. The correct trend of magnitude of dissociation constant (k_a) of their hydrides is H₂L > H₂M > H₂J > H₂Q. The element ‘M’ in the sequence is