First slide

Faraday's Laws

Question

A 4.0 M aqueous solution of NaCl is prepared and 500 mL of this solution is electrolysed. This leads to evolution of chlorine gas at one of the electrodes.
(Q) Calculate the number of moles of chlorine gas evolved during the electrolysis.

Easy

A

0.5
B

1.0
C

2.0
D

3.0

Solution

no. of moles of NaCl = $\frac{4 \times 500}{1000} = 2 moles$
$2 NaCl \to 2 {Na}^{+} + 2 {Cl}^{-} 2 {Cl}^{-} \to {Cl}_{2} + 2 e^{-}$
1 mole of Cl₂ is produced.

Get Instant Solutions

When in doubt download our app. Now available Google Play Store- Doubts App

Recieve an sms with download link

Doubts App

OR

SCAN ME

Doubts App

Doubts App