0.01 M solution of KCI and BaCl2 are prepared in water. The freezing point of KCl is found to be -2oC. What is the freezing point of BaCl2 to be completely ionised?

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-3oC

+3oC

-2oC

-4oC

answer is A.

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Detailed Solution

i for KCl=2,i for BaCl2=3∵ ΔTf∝i;ΔTf(KCl)ΔTfBaCl2=23∴ ΔTfBaCl2=32×2=3∘C∴ Freezing point of KCl=−3∘C

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