A magnetic moment of 1.73 B.M. will be shown by one among the following:
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a
CuNH342+
b
NiCN42−
c
TiCl4
d
CoCl64−
answer is A.
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Detailed Solution
∵ nn+2=1.73∴ n=1, i.e., species has one unpaired electron. Thus species is CuNH342+Cu2+ in CuNH342+ has configurationOne electron is shifted from 3d to 4p in complex formation.