The magnetic moment of a complex ion is 2.83 B.M. The complex ion is :
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a
VH2O63+
b
CrH2O63+
c
Cu(CN)42−
d
MnCl42−
answer is A.
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Detailed Solution
μ→=2.83BM⇒ Number of unpaired e−must be =2 (a) VH2O63+ Number of unpaired e−=2 (b) CrH2O63+ Number of unpaired e−=3 (c) Cu(CN)42− Number of unpaired e−=1 (d) MnCl42− Number of unpaired e−=5