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The magnetic moment of K3[Fe(CN)6] is found to be 1.73 BM. How many unpaired electron(s) is/are present per molecule?

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By Expert Faculty of Sri Chaitanya
a
2
b
3
c
4
d
1

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detailed solution

Correct option is D

μ=nn+21.73=nn+2So, n=1


Similar Questions

Among NiCO4,NiCN42,NiCl42 species, the hybridization states at the Ni atom are, respectively

(At. no. of Ni = 28)

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