The magnetic moment of KO₂ at room temperature is __________ BM.

$\text{ Magnetic }\mu =n\sqrt{n(n+2)}\mathrm{BM}$

where n is the number of unpaired electron.

KO₂ has 1 (one) unpaired electron

$\begin{array}{r}=\sqrt{1(1+2)}\mathrm{BM}\\ =\sqrt{3}=1.73\mathrm{BM}\end{array}$