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answer is 2.83.
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Detailed Solution
The electronic configuration of N22− ion is: KK∗(σ2s)2σ∗2s2π2px2≡π2py2σ2pz2π∗2px1≡π∗2py1N22− ion is paramagnetic due to presence of 2 unpaired e 's in π2px1 and π∗2py1. Its magnetic moment μMM is: μMM=n(n+2)BM=2(2+2)=8BM=2.83BM