The magnitude of the change in oxidizing power of the MnO4−/Mn2+ couple is x×10−4V, if the H+ concentration is decreased from 1 M to 10−4M at 25°C . (Assume concentration of MnO4-and Mn2+to be same on change in H+ concentration). The value of x is ________(Rounded off to the nearest integer) Given:2.303RTF=0.059
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answer is 3776.
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Detailed Solution
MnO4−+8H++5e−→Mn+2+4H2OE=E0-0.0595log10Mn+2H+8MnO4-E=E0-0.0595log11=E0E=E0-0.0595log110-48=E0-0.0595log1032E0-E0+0.0595×32=0.3776 V