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The major product formed in the following reaction is

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The dissolving metal reduction of aromatic rings, known as the Birch reduction. Sodium metal is dissolved in liquid NH3 to give an intense blue solution. Blue is the colour of solvated electron which is strong reducing agent due to their small size and high energy.Na+NH3→Na++e−NH3n

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COLUMN - I Reaction		COLUMN - II Product
a.	$\begin{aligned} (COOH)_{2} \cdot 2 H_{2} O \frac{Δ}{105^{\circ} C} \to \\ (I) \end{aligned}$	p.	$2 {CO}_{2} + H_{2} O$
b.	$\begin{aligned} (I) \frac{Δ at 200^{\circ} C}{or} → \\ H_{2} {SO}_{4}, at 90^{\circ} C \end{aligned}$	q.	$(COOH)_{2}$
c.		r.	$CO + {CO}_{2} + H_{2} O$
d.	$(I) \frac{Δ}{{KMnO}_{4}}$	s.	Carbon suboxide $(O = C = C = C = O)$
e.	$2 HCOONa \frac{Δ, 360^{\circ} C}{H_{3} O^{\oplus}}$	t.	$MeCOOH + {CO}_{2}$
f.