Mass of 1 amu gives energy equal to

E=mc2, where m= mass defect c= velocity of light =3×1010cms−1∴E=1.66×10−24×3×10102=14.94×10−4erg=1.494×10−10J                            1MeV=1.602×10−13J∴E=1.494×10−101.602×10−13=931.5MeV