The mass of copper deposited from a solution of CuSO4 by passage of 5 A current for 965 second is(Mol. wt. of Copper = 63.5)
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a
15.875 g
b
1.5875 g
c
4825 g
d
96500 g
answer is B.
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Detailed Solution
Current (I) = 5 A and time (t) = 965 secWe know that equivalent weight of copper =Molecular weightValency=63.52and quantity of electricity passed in coulomb =current×time=5×965=4825 C. Since 96500 coulombs will deposit 63.52g of copper, therefore 4825 coulombs will deposit =63.5×482596500×2=1.5875 g