First slide

Chemical reactions and calculations

Question

The mass of copper that will be deposited at cathode in electrolysis of 0.2 M solution of copper sulphate when a quantity of electricity equal to that required to liberate 2.24 L of hydrogen from 0.1 M aqueous H₂SO₄ is passed (atomic mass of Cu = 63.5) will be

Moderate

Solution

$1 F = 1 Eq of H_{2} = 11.2 L of H_{2}$
$11.2 L of H_{2} = 1 Eq of H_{2}$
$2.24 L of H_{2} = \frac{2.24}{11.2} = 0.2 Eq$
$∴ 0.2 Eq of Cu will be deposited.$
$1 Eq of Cu = \frac{63.5}{2} g$
$0.2 Eq of Cu = \frac{63.5}{2} \times 0.2 = 6.35 g$

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