First slide

Quantum mechanical model of the atom

Question

The mass of an electron is m, charge is e and it is accelerated from rest through a potential difference of V volts. The velocity acquired by electron will be

Moderate

A

$\sqrt{\frac{V}{m}}$
B

$\sqrt{\frac{e V}{m}}$
C

$\sqrt{\frac{2 e V}{m}}$
D

Zero

Solution

When an electron of charge e and mass m is accelerated with a potential difference of V volts K.E. = eV.
$\Rightarrow \frac{1}{2} m v^{2} = e V o r v^{2} = \frac{2 e V}{m}$
$\Rightarrow v = \sqrt{\frac{2 e V}{m}}$

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