Q.

The mass of 70% H2SO4 required for neutralization of one mole of NaOH is

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a

70 g

b

35 g

c

30 g

d

95 g

answer is A.

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Detailed Solution

nNaOH = 1moleNo.of equivaents of NaOH = 1Number of eq of H2SO4 = Number of eq of NaOHWt of 100% pure H2SO4 required = 49gWt of 70% pure H2SO4 required = 49 x 100/70                                                 = 70g
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