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Q.

The mass of N2F4 produced by the reaction of 2.0 g of NH3 and 8.0 g F2 is 3.56 g. what is the per cent yield ?2NH3 + 5F2 → N2F4 + 6HF

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a

79.0

b

71.2

c

84.6

d

None of these

answer is D.

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Detailed Solution

Limiting reagent is NH32NH3 + 5F2 → N2F4 + 6HF2 x 17g NH3 give 66g N2F42g will give = 6634×2=3.88g N2F4% yield = 3.563.88×100=91.75%
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