Q.

The mass of a non-volatile solute (molecular mass = 40) which should be dissolved in 114 g octane to reduce its vapour pressure to 80% will be

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a

20 g

b

30 g

c

10 g

d

40 g

answer is C.

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Detailed Solution

If p0=100, then ps=80p=p0xA80=100×xAxA=0.80xA=nAnA+nB=114/114114/114+wB/400.8=11+wB/401+wB40=10.8wB=10g                                                    OR                   Po-PsPo= XB 20100=wB40wB40+114114             15=0.025wB1+ 0.025wBwB= 10g
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