The mass of oxygen that would be required by carbon to produce enough CO  which completely reduces 1.6 kg Fe2O3 (at. Mass Fe=56 ) is:

2C+O2→2CO]×33 CO +Fe2O3  → 2 Fe +3CO2] ×26 C+3 O2 + 2Fe2 O3  → 4Fe +6CO23×32          2(112+48)=96 kg       =320 kg320 kg   Fe2O3  require O2=96 kg 1.6kg  Fe2O3  require O2=96320×1.6 =0.48 kg  =480 g