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The mass of a particle is 10−10g and its radius is 2×10−4cm. If its velocity is 10−6cmsec−1 with 0.0001% uncertainty in measurement, the uncertainty in its position is

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a

5.2×10−8m

b

5.2×10−7 m

c

5.2×10−6 m

d

5.2×10−9

answer is A.

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Detailed Solution

m=10−10g⇒10−13kgΔv=0.0001100×10−6×10−2=10−14msec−1=Δx⋅Δp=h4π⇒Δx=h4πΔp=h4π⋅mΔvΔx=6.62×10−344×3.14×10−13×10−14Δx=6.6212.56×10−3410−27;Δx=5.2×10−8m

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