The mass of potassium dichromate crystals required to oxidise $$750$$ $$cm3$$ of $$0.6$$ M Mohr's salt solution is (Given$$, molar mass : potassium dichromate $$=$$ $$294$$, Mohr's salt $$=$$ $$392)

Question

The mass of potassium dichromate crystals required to oxidise $$750$$ $$cm3$$ of $$0.6$$ M Mohr's salt solution is (Given$$, molar mass : potassium dichromate $$=$$ $$294$$, Mohr's salt $$=$$ $$392)

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Mohr's salt is $$FeSO4$$·$$NH42SO4$$·$$6H2OOnly$$ oxidisable part $$isFe2+Fe2+$$⟶$$Fe3++e-$$×$$6Cr2O72-+14H++6e-$$⟶$$2Cr3++7H2O6Fe2++Cr2O72-+14H+$$⟶$$6Fe3++2Cr3++7H2O$$ Millimoles of $$Fe2+=750$$×$$0.6=450$$ Moles of $$Fe2+=4501000=0.450$$ $$mol6$$ moles of $$Fe2+$$≡$$1$$ $$molCr2O72-$$∴$$0.450$$ mole $$Fe2+$$≡$$0.4506=0.075$$ mol $$Cr2O72-=$$ $$0.075$$ x $$294$$ $$g=$$ $$22.05$$ g

The mass of potassium dichromate crystals required to oxidise 750 ${cm}^{3}$ of 0.6 M Mohr's salt solution is (Given, molar mass : potassium dichromate = 294, Mohr's salt = 392)

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The mass of potassium dichromate crystals required to oxidise 750 cm3 of 0.6 M Mohr's salt solution is (Given, molar mass : potassium dichromate = 294, Mohr's salt = 392)

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The mass of potassium dichromate crystals required to oxidise 750 ${cm}^{3}$ of 0.6 M Mohr's salt solution is (Given, molar mass : potassium dichromate = 294, Mohr's salt = 392)