Match each coordination compound in Column I with an appropriate pair of characteristics from Column II and select the correct answer using the code given below the lists
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a
a→s, b → p; c→ q; d → r
b
a→r, b → p; c→ s; d → q
c
a→r, b → p; c→ q; d → s
d
a→q, b →p; c→ r; d → s
answer is B.
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Detailed Solution
.presence of unpaired electron gives paramagnetic nature and absence of unpaired electron gives diamagnetic nature