Match each coordination compound in Column I with an appropriate pair of characteristics from Column II and select the correct answer using the code given below the lists

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a→s, b → p; c→ q; d → r

a→r, b → p; c→ s; d → q

a→r, b → p; c→ q; d → s

a→q, b →p; c→ r; d → s

answer is B.

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Detailed Solution

.presence of unpaired electron gives paramagnetic nature and absence of unpaired electron gives diamagnetic nature

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