Match the following columns. 

	Column I		Column II
A.	${\mathrm{Fe}}^{3+}\text{ and }{\mathrm{I}}^{-}$	p.	${\mathrm{E}}_{\mathrm{cell}}^{\circ }=+\mathrm{ve}$
B.	${\mathrm{Fe}}^{3+} \mathrm{and} {\mathrm{Br}}^{-}$	q.	${\mathrm{\Delta G}}^{\circ }=+ \mathrm{ve}$
C.	$\mathrm{Zn}\text{ and }{\mathrm{H}}^{+}$	r.	${\mathrm{E}}_{\text{cell }}^{\circ }=-{\mathrm{E}}_{\text{electrode }}^{\circ }$
D.	$\mathrm{Br} \mathrm{and} {\mathrm{Fe}}^{2+}$	s.	${\mathrm{\Delta G}}^{\circ }=-\mathrm{ve}$

$\left[\text{ Given, }{\mathrm{E}}_{{\mathrm{Fe}}^{3+}/{\mathrm{Fe}}^{2+}}^{\circ }=0.77,{\mathrm{E}}_{\left[\frac{1}{2}{\mathrm{I}}_2/1^{-}\right]}^{\circ }=+0.54\right.$
$\left.{\mathrm{E}}_{1/2{\mathrm{Br}}_2/{\mathrm{Br}}^{-}}=1.09,{\mathrm{E}}_{{\mathrm{Zn}}^{2+}/\mathrm{Zn}}^{{\circ }^{\circ }}=-0.76\right]$

A→p,s; B→q; C→p,r,s; D→p,sA reaction is feasible, if its Ecello value is positive.A. Fe3+(aq)+I−(aq)⟶Fe2+(aq)+12I2(g)    Ecell ∘=EFe3+/Fe2+−E∘1/2I2/1−=(0.77−0.54)=0.23     The reaction is feasible.     i.e. ΔG∘=−veB. Fe3+(aq)+Br−(aq)⟶Fe2+(aq)+12Br2(g)    Ecell ∘=EFe3+/Fe2+∘−E∘1/2Br2/Br−=0.77−1.09=−0.32V   The reaction is not feasible.     i.e.  ΔG∘=+veC.12Br2(aq)+Fe2+(aq)⟶Br−(aq)+Fe3+(aq)     Ecell ∘=E1/2Br2/Br−∘−EFe3+/Fe2+=1.09−0.77=0.32V    The reaction is feasible.    ΔG∘=−ve