Match the following columns.
Column I Column II
A. ${Fe}^{3 +} and I^{-}$ p. $E_{cell}^{\circ} = + ve$
B. ${Fe}^{3 +} and {Br}^{-}$ q. ${ΔG}^{\circ} = + ve$
C. $Zn and H^{+}$ r. $E_{cell}^{\circ} = - E_{electrode}^{\circ}$
D. $Br and {Fe}^{2 +}$ s. ${ΔG}^{\circ} = - ve$
$[Given, E_{{Fe}^{3 +} / {Fe}^{2 +}}^{\circ} = 0 .77, E_{[\frac{1}{2} I_{2} / 1^{-}]}^{\circ} = + 0 .54$
$E_{1 / 2 {Br}_{2} / {Br}^{-}} = 1 .09, E_{{Zn}^{2 +} / Zn}^{\circ^{\circ}} = - 0 .76]$

Difficult

Solution

$A \to p, s; B \to q; C \to p, r, s; D \to p, s$
A reaction is feasible, if its $E_{cell}^{o}$ value is positive.
A. ${Fe}^{3 +} (aq) + I^{-} (aq) ⟶ {Fe}^{2 +} (aq) + \frac{1}{2} I_{2} (g)$
   $E_{cell}^{\circ} = E_{({Fe}^{3 +} / {Fe}^{2 +})} - {E^{\circ}}_{1 / 2} I_{2 / 1^{-}} = (0 .77 - 0 .54) = 0 .23$
The reaction is feasible.
   $i.e. {ΔG}^{\circ} = - ve$
B. ${Fe}^{3 +} (aq) + {Br}^{-} (aq) ⟶ {Fe}^{2 +} (aq) + \frac{1}{2} {Br}_{2} (g)$
   $E_{cell}^{\circ} = E_{({Fe}^{3 +} / {Fe}^{2 +})}^{\circ} - {E^{\circ}}_{1 / 2 {Br}_{2} / {Br}^{-}} = 0 .77 - 1 .09 = - 0 .32 V$
The reaction is not feasible.
   $i.e. {ΔG}^{\circ} = + ve$
C. $\frac{1}{2} {Br}_{2} (aq) + {Fe}^{2 +} (aq) ⟶ {Br}^{-} (aq) + {Fe}^{3 +} (aq)$
$E_{cell}^{\circ} = E_{(1 / 2 {Br}_{2} / {Br}^{-})}^{\circ} - E_{({Fe}^{3 +} / {Fe}^{2 +})} = 1 .09 - 0 .77 = 0 .32 V$
The reaction is feasible.
   ${ΔG}^{\circ} = - ve$

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