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a
1
b
2
c
3
d
4
answer is B.
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Detailed Solution
I.E…C < O < N < F < Ne…due to symmetrical configuration in Nitrogen….Higher IP than expected;EGE… O < Te < Se < S …..due to small size and inter electronic repulsions in Oxygen…. lower EGE than expected ;Metallic character…Mg < Ca < K < Cs…..2nd group < 1st group….down the group, metallic character increases ;Atomic radius…F < O < S < Se ….. F < O…. left to right decreases; O < S < Se…..down the group increases ;