Match the items of Column I and Column II on the basis of data given below. $$EF2/F$$−∘$$=2.87V$$,$$ELi+/Li$$∘$$=$$−$$3.5V$$,$$EAu3+/Au$$∘$$=1.4V$$,$$EBr2/Br$$−∘$$=1.09V$$

Question

Match the items of Column I and Column II on the basis of data given below.        $$EF2/F$$−∘$$=2.87V$$,$$ELi+/Li$$∘$$=$$−$$3.5V$$,$$EAu3+/Au$$∘$$=1.4V$$,$$EBr2/Br$$−∘$$=1.09V$$

Infinity Learn · Accepted Answer

A. → (3)      B. → (1)      C. → (7)  D. →(5)  E. → (4)      F. → (2)      G. →(6)    A. $$F2$$ it a $$non-metal$$ and best oxidising agent because SRP of $$F2$$ is $$+$$ $$2.87$$ V.B. Li is a metal and strongest reducing agent because SRP of Li is $$-$$ $$3.05$$ V.C. $$Au3+$$ is a metal ion which is an oxidising agent as SRP of $$Au3+$$ is $$+1.40$$ V.D. $$Br-$$ is an anion that can be oxidised by $$Au3+$$ as $$Au3+$$ (Eo$$ $$=$$ $$1.40) is greater than $$Br-$$ (Eo$$ $$=$$ $$1.09$$ $$V).E. Au is an un reactive metal.F. $$Li+$$ is a metal ion having least value of SRP $$(-3.05$$ $$V)$$, hence it is the weakest oxidising agent.G. $$F-$$ is an anion which is the weakest reducing agent as $$F-$$ $$/$$ $$F2$$ has low oxidation potential $$(-2.87$$ $$V)$$.

Q.

Want to Fund your own JEE / NEET / Foundation preparation ??

Get Expert Academic Guidance – Connect with a Counselor Today!