Match List-I (complex ions) with List-II (number of unpaired electrons) and select the correct answer using the codes given below lists:List-I(Complex ions) List-II(Number of Unpaired ElectronCode :

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answer is C.

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Detailed Solution

CrF64−n=43d4MnF64−n=53d5CrCN64−n=23d4MnCN64−n=13d5n = number of unpaired electrons and that can be calculated by CFT.

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