Match the type of unit cell given in Column I with the features given in Column II.

A. →(2,3)  B. →(3,4)  C. →(3,5)  D. →(1,4)A. For primitive unit cell, a = b = c     Total number of atoms per unit cell = 1/8 x  8 = 1    Here, 1/8 is due to contribution of each atom present at corner.B. For body centred cubic unit cell, a = b = c    This lattice contain atoms at corner as well as body centre.    Contribution due to atoms at corn€r = 1/ 8 x 8 = 1 Contribution    Due to atoms at body centre = 1C. For face centred unit cell, a = b = c     Total constituent ions per unit cell present at corners                   =18×8=1   Total constituent ions per unit cell present at face centre                  =12×6=3D.For end centered orthorhombic unit cell,a≠b≠c   Total contribution of atoms present at corner                  =18×8=1   Total contribution of atoms present at end centre                  =12×2=1Hence, other than corner it contain total one atom per unit cell.