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a
36g of water
b
28g of carbon monoxide
c
46g of ethyl alcohol
d
54g of nitrogen pentoxide
answer is A.
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Detailed Solution
18 g of H2O=6.02×1023 molecules of H2O ∴36 g of H2O=2×6.02×1023 molecules of H2O=12.04×1023 molecules of H2O 28 g of CO=6.02×1023 molecules of CO 46 g of C2H5OH=6.02×1023 molecules of C2H5OH 108 g of N2O5=6.02×1023 molecules of N2O5 ∴54 g of N2O5=12×6.02×1023 molecules of N2O5=3.01×1023 molecules of N2O5Therefore, 36g of water has the highest of molecules