Q.
Maximum number of water molecules are present in
see full answer
Talk to JEE/NEET 2025 Toppers - Learn What Actually Works!
Real Strategies. Real People. Real Success Stories - Just 1 call away
An Intiative by Sri Chaitanya
answer is 1.
(Unlock A.I Detailed Solution for FREE)
Ready to Test Your Skills?
Check your Performance Today with our Free Mock Test used by Toppers!
Take Free Test
Detailed Solution
(1) Density of water 1g/cc 18 ml of H2O = 18g of H2O = NA molecules 1.8 ml of H2O = 1.8g of H2O = NA10 molecules(2) 1 mole = NA molecules 10−4moles - ? NA104molecules(3) 22.4 lit of H2O (g) at STP - NA molecule 2.24x10−4lit of H2O (g) at STP - ? NA105(4) 18g = NA molecules1.8×10−2g = ? NA103
Watch 3-min video & get full concept clarity