Q.

Maximum possible electrons in Na, for which n + l + m = 3 is/are

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a

6

b

3

c

4

d

5

answer is B.

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Detailed Solution

Na(11):1s22s22p63s1For  2pz2,n+1+m=3For 3s1,n+1+m=3
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Get ₹ 1 crore* worth scholarship for JEE / NEET / Foundation
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Best Books for NEET
How to Join IIT after 10th
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