The maximum work done in Joules expanding 16g of oxygen at 300 K and occupying a volume of 7dm3 isothermally until the volume becomes 35 dm3 is a ×103 J
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answer is -2.01.
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Detailed Solution
Maximum work is always obtained in a reversible process∴w=−2.303nRTlogV2−V1∵nO2=(w/m)=(16/32);R=8.314J/K mole T=300K,V1=7dm3,V2=35dm3∴w=−2.303×(16/32)×8.314×300×log357 =−2.01×103J