Mechanism of a reaction A2+B2→2ABis shown below then its order is A2⇌A+A fastA+B2→AB+B slowA+B→A+B fast

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Zero

1/2

3/2

answer is D.

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Detailed Solution

kc=[A]2/A2⇒[A]=Kc12⋅A212r=K1[A]B2r=K1Kc12⋅A212B2r=K⋅A212B21

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