First slide

2nd Law of Thermodynaimcs

Question

The melting point of a solid is 300 K and its latent heat of fusion is 600 cal mol-1. The entropy change for the fusion of 1 mole of the solid (in cal K-1 ) at the same temperature would be :

Moderate

Solution

$\Delta {S_{fusion}} = \frac{{\Delta {H_{fusion}}}}{T} = \frac{{600}}{{300}} = 2cal/K$

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