MetaI carbides on reaction with H2O form CH4.Carbide can be

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CaC2

Mg3C2

Be2C

SiC

answer is C.

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Detailed Solution

(1) CaC2+H2O⟶Ca(OH)2+CH≡CH(2) Mg2C3+H2O⟶Mg(OH)2+CH3C≡CH(3) Be2C+H2O⟶Be(OH)2+CH4

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