A metal crystallises in a face centred cubic structure. If the edge length of its unit cell is 'a', the closest approach between two atoms in metallic crystal will be:
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a
2a
b
a2
c
2a
d
22a
answer is B.
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Detailed Solution
for fcc then b=4r=2aa=4r2=22r⇒r=a22 Therefore, distance of closest approach =2r=2×a22=a2