A metal crystallizes in two cubic phases, face centred cubic (fcc) and body centred cubic (bcc) whose unit cell lengths are 3.5A0 and 3.0A0 respectively. Calculate the ratio of density of fcc and bcc.
see full answer
Your Exam Success, Personally Taken Care Of
1:1 expert mentors customize learning to your strength and weaknesses – so you score higher in school , IIT JEE and NEET entrance exams.
An Intiative by Sri Chaitanya
a
2.123
b
1.259
c
5.124
d
3.134
answer is B.
(Unlock A.I Detailed Solution for FREE)
Best Courses for You
JEE
NEET
Foundation JEE
Foundation NEET
CBSE
Detailed Solution
ρ = Z×MNA×a3For fcc centred cubic cell Z=4, a=3.5A0∴ρ(fcc)=4×MNA×(3.5)3 …… (i) For bcc lattice Z=2,a=3.0A0ρ(bcc)=2×MmNA×(3.0)3 …… (ii) From equations (i) and (ii) ∴ρ(fcc)ρ(bcc)=42×33(3.5)3=4×3×3×32×3.5×3.5×3.5=1.259