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Q.

A metal gives two chlorides A and B. A gives black precipitate with NH4OH and B gives white. With KI, B gives a red precipitate soluble in excess of KI. A and B are respectively

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a

HgCl2 and Hg2Cl2

b

Hg2Cl2 and HgCl2

c

HgCl2 and ZnCl2

d

ZnCl2 and HgCl2

answer is B.

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Detailed Solution

Hg2Cl2A+2NH4OH→  H2N−Hg−Cl+HgBlack↓+NH4Cl+2H2OHgCl2+2NH4OH→  HgNH2Cl+NH4Cl+H2O(B)(White)HgCl2+2KI⟶HgI2(Red)↓+2KClHgI2+2KI(excess)⟶K2HgI4
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