Q.

A metal has density of 4500 kg/m3 with an fcc crystal structure and edge length is 400 pm. The number of unit cells present in 1 kg of the metal is n × 1024. Value of n is ________. (upto two decimal place)

Unlock the Full Solution and Master the Concept

Get a detailed solution and exclusive access to our masterclass to ensure you never miss a concept

By Expert Faculty of Sri Chaitanya

answer is 3.47.

(Detailed Solution Below)

Ready to Test Your Skills?

Check your Performance Today with our Free Mock Test used by Toppers!

Take Free Test

Detailed Solution

Volume available =1kg4500kg/m3=14500m3 Vol. of a unit cell =400×10−123m3 No. of unit cell =14500×400×10−123=3.47×1024

Choose your Grade and Exam

Connect with our

Expert Counsellors

access to India's best teachers with a record of producing top rankers year on year.

+91

We will send a verification code via OTP.