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A metal has a fcc lattice. The edge length of the unit cell is 404 pm. The density of the metal is $2.72 g {cm}^{- 3}$ The molar mass of the metal is $(N_{A} Avogadro's constant = 6.02 \times 10^{23} {mol}^{- 1})$

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detailed solution

Correct option is A

d=ZMNAa3M=d×NA×a3Z=2.72×6.023×1023×404×10−1034M=27gmol−1

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A metal has a fcc lattice. The edge length of the unit cell is 404 pm. The density of the metal is 2.72gcm−3 The molar mass of the metal is NA Avogadro's constant =6.02×1023mol−1

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Ready to Test Your Skills?

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A metal has a fcc lattice. The edge length of the unit cell is 404 pm. The density of the metal is $2.72 g {cm}^{- 3}$ The molar mass of the metal is $(N_{A} Avogadro's constant = 6.02 \times 10^{23} {mol}^{- 1})$