Q.

A metal has a fcc lattice. The edge length of the unit cell is 404 pm. The density of the metal is 2.72gcm−3 The molar mass of the metal is NA Avogadro's constant =6.02×1023mol−1

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a

27gmol−1

b

20gmol−1

c

40gmol−1

d

30gmol−1

answer is A.

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Detailed Solution

d=ZMNAa3M=d×NA×a3Z=2.72×6.023×1023×404×10−1034M=27gmol−1
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