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A metal oxide has the formula Z2O3. It can be reduced by hydrogen to give a free metal and water. 0.1596 gm of the metal oxide requires 6mg of hydrogen for complete reduction. The atomic mass of the metal is

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answer is 4.

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Detailed Solution

Z2O3 + 3H2 → 2Z + 3H2OWeight of Z2O3 = 0.1596gWeight of Hydrogen = 6 x 10-3 g   EZ = 18.6Ew of metal = 18.6Formula of metal Oxide = Z2O3Valency of 'Z' = 3;Aw of metal = (18.6 x 3) = 56
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