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Metallic copper dissolves in concentrated HNO3 to form Cu(NO3)2 and liberates NO2 gas. Number of electrons appearing in balanced oxidation half reaction and balanced reduction half reaction is respectively x and y. Ratio between x and y is

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a

1 : 1

b

1 : 2

c

2 : 1

d

1 : 3

answer is C.

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Detailed Solution

Balanced oxidation half reaction Cu →Cu+2 + 2 e-Balanced reduction half reactionNO3-+2H++e-→NO2+H2Ox = 2 y =1Ratio = 2 : 1

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