Methylation of Diborane give $\left[\mathrm{Me}=\mathrm{methyl} \mathrm{group}\right]$

• A

  ${\mathrm{B}}_2{\left(\mathrm{Me}\right)}_6$

• B

  ${\mathrm{B}}_2\mathrm{H}{\left(\mathrm{Me}\right)}_5$

• C

  ${\mathrm{B}}_2{\mathrm{H}}_2{\mathrm{Me}}_4$

• D

  All the above