A 400 mg iron capsule contains 100 mg of ferrous fumarate, (CHCOO)2Fe. The percentage of iron present in it is approximately
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a
8%
b
25%
c
14%
d
33%
answer is A.
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Detailed Solution
Molecular weight of (CHCOO)2Fe = 170Fe present in 100 mg of (CHCOO)2Fe = 17=56170×100mg=32.9mgThis is present in 400 mg of capsule% of Fe in capsule =32.9400×100=8.2.