10 milli equivalents of Phosphoric acid is dissolved in a 100ml solution. Normality of the solution is…………N

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0.1

0.05

0.025

0.2

answer is A.

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Detailed Solution

N=Number of gram equivalents×1Vl; N=Number of gram equivalents×1000Vml; Number of gram equivalents=wsoluteGEW of solute; N=10×10-3×1000100=0.1 N ;

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