10 millimoles of a diacidic base exactly neutralises 100ml of an acid. Then the Normality of that acid is

At equivalent point (neutralization point)    VaNa = VbNbNo.of gram equivalents of acid = No.of gram equivalents of  baseNo.of milli equivalents of acid = No.of milli equivalents of  base     100(Na) = millimoles X acidity     100(Na) = 10(2)       Na = 0.2NNormality of acid = 0.2 N