The minimum number of moles of O2 required for complete combustion of 1 mole of propane and 2 moles of butane is

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answer is 18.

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Detailed Solution

(i) Combustion of propane :C3H8+5O2(g)→3CO2(g)+4H2O 1 mole 5 mole(ii) Combustion of butane :C4H10+132O2→4CO2(g)+5H2O1 mole⇒132mole2 mole = 132×2=13Total moles of O2 = 13 + 5 = 18 mole

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