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Q.

The minimum voltage required to electrolyse alumina in the Hall-Heroult process is [Given,ΔGfoAl2O3=−1520 kJ/mol and ΔGfo(Al2O3)=-1520 kJ/mol and ΔGfo (CO2) = 394 kJ/mol]

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a

1.60 V

b

1.575 V

c

1.312 V

d

-2.62 V

answer is A.

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Detailed Solution

In Hall-Heroult process the following reactions occur3C+2Al2O3⟶4Al+3CO2ΔGo=3ΔGfoCO2−2ΔGfoAl2O3=3(−394)−2(−1520)=1858kJΔGo=−nFE∘ or =−E∘=ΔGonF=1858×100012×96500=1.60V
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