Q.

A mixture of boric acid with ethyl alcohol burns with green edged flame due to the formation of

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a

Ethyl borax

b

Ethyl borate

c

Methyl borax

d

Methyl borate

answer is B.

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Detailed Solution

H3BO3  +  3C2H5OH  →    BOC2H53  +  3H2O
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Related Blogs
Get ₹ 1 crore* worth scholarship for JEE / NEET / Foundation
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Best Books for NEET
How to Join IIT after 10th
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