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Q.

A mixture of 0.3 mole of H2 and 0.3 mole of I2 is allowed to react in a 10 litre evacuated flask at 5000C. The reaction is H2+I2 ⇋  2HI, the K is found to be 64. The amount of unreacted I2 at equilibrium is

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a

0.15 mole

b

0.06 mole

c

0.03 mole

d

0.2 mole

answer is B.

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Detailed Solution

KC=HI2H2 I2;  64 = x20.03 × 0.03x2=64 × 9 × 10-4x=8 × 3 × 10-2=0.24x is the amount of HI at equilibrium amount of I2 at equilibrium will be 0.30 - 0.24 = 0.06
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