40 % mixture of 0.2 mole of N2 and 0.6 mole of H2 reacts to give NH3 according to the equation N2+3H2⇌2NH3(g) (g) (g) at constant temperature and pressure. Then the ratio of the final volume to the initial volume of gases is

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4 : 5

8 : 5

7 : 10

5 : 4

answer is A.

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Detailed Solution

N2+3H2⇌2NH3 Initial 0.2 0.6 0Reacted 0.08 0.24 0.16Equi 0.12 0.36 0.16Initial moles = 0.2 + 0.6 = 0.08Final moles = 0.12 + 0.36 + 0.16 = 0.64At constant T and P , V α n∴ 0.640.8=45=4:5

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