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Q.

40 % mixture of 0.2 mole of N2  and 0.6 mole of H2  reacts to give NH3  according to the equation N2+3H2⇌2NH3(g)       (g)              (g)  at constant temperature and pressure. Then the ratio of the final volume to the initial volume of gases is

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a

4 : 5

b

8 : 5

c

7 : 10

d

5 : 4

answer is A.

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Detailed Solution

N2+3H2⇌2NH3 Initial   0.2         0.6                0Reacted 0.08   0.24           0.16Equi       0.12   0.36          0.16Initial moles = 0.2 + 0.6 = 0.08Final moles  = 0.12 + 0.36 + 0.16 = 0.64At constant T and P , V α  n∴  0.640.8=45=4:5
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40 % mixture of 0.2 mole of N2  and 0.6 mole of H2  reacts to give NH3  according to the equation N2+3H2⇌2NH3(g)       (g)              (g)  at constant temperature and pressure. Then the ratio of the final volume to the initial volume of gases is