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Q.

A mixture of Ne and Ar at 250 has a total K.E.=3 kJ in a closed vessel the total mass of Ne and Ar is 30 g. Find mass % of Ne in gaseous mixture at 250 K

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a

61.63

b

38.37

c

50%

d

28.3

answer is D.

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Detailed Solution

K=32nTRT⇒nT=3000×23×250×8.3143×103=32nT×8.314×250x20+30−x40=28.314 %Ne=28.3
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